{"id":755,"date":"2024-10-10T22:12:44","date_gmt":"2024-10-10T16:42:44","guid":{"rendered":"https:\/\/codexplained.in\/?p=755"},"modified":"2025-11-24T15:53:42","modified_gmt":"2025-11-24T10:23:42","slug":"print-inverted-pyramid-pattern","status":"publish","type":"post","link":"https:\/\/codexplained.in\/?p=755","title":{"rendered":"Print Inverted Pyramid Pattern"},"content":{"rendered":"
\n#include <stdio.h>\n\nint main() {\n    int rows;\n\n    \/\/ Prompt user for the number of rows\n    printf("Enter the number of rows for the inverted pyramid: ");\n    scanf("%d", &rows);\n\n    \/\/ Outer loop for each row\n    for (int i = 0; i < rows; i++) {\n        \/\/ Inner loop for printing spaces\n        for (int j = 0; j < i; j++) {\n            printf(" "); \/\/ Print space\n        }\n        \/\/ Inner loop for printing stars\n        for (int k = 0; k < (2 * (rows - i) - 1); k++) {\n            printf("*"); \/\/ Print star\n        }\n        \/\/ Move to the next line after each row\n        printf("\\n");\n    }\n\n    return 0;\n}\n\n<\/pre><\/div>\n\n\n
Explanation of the Code<\/h2>\n\n\n\n
Header Files<\/strong>: The program includes stdio.h<\/code> to use standard input and output functions.<\/p>\n\n\n\n
Getting User Input<\/strong>:<\/p>\n\n\n\n
We declare an integer variable rows<\/code> to store the number of rows for the inverted pyramid.<\/p>\n\n\n\n
We prompt the user to enter the desired number of rows.<\/p>\n\n\n\n
Outer Loop<\/strong>:<\/p>\n\n\n\n
The outer loop (for (int i = 0; i < rows; i++)<\/code>) runs once for each row of the inverted pyramid.<\/p>\n\n\n\n
Inner Loop for Spaces<\/strong>:<\/p>\n\n\n\n
The first inner loop (for (int j = 0; j < i; j++)<\/code>) prints spaces to create the indentation. The number of spaces increases as we move down the rows.<\/p>\n\n\n\n
Inner Loop for Stars<\/strong>:<\/p>\n\n\n\n
The second inner loop (for (int k = 0; k < (2 * (rows - i) - 1); k++)<\/code>) prints the stars. The number of stars decreases as we go down each row, calculated by 2\u00d7(rows\u2212i)\u221212 \\times (\\text{rows} – i) – 12\u00d7(rows\u2212i)\u22121.<\/p>\n\n\n\n
New Line<\/strong>:<\/p>\n\n\n\n
After printing the stars for each row, we use printf(\"\\n\")<\/code> to move to the next line.<\/p>\n\n\n\n
Output:<\/h2>\n\n\n\n
Enter the number of rows: 5<\/p>\n\n\n\n
*********\n *******\n  *****\n   ***\n    *\n<\/code><\/pre>\n\n\n\n
<\/p>\n