{"id":1104,"date":"2025-11-21T08:52:23","date_gmt":"2025-11-21T03:22:23","guid":{"rendered":"https:\/\/codexplained.in\/?p=1104"},"modified":"2025-11-21T08:52:23","modified_gmt":"2025-11-21T03:22:23","slug":"simple-calculator-using-switch-case","status":"publish","type":"post","link":"https:\/\/codexplained.in\/?p=1104","title":{"rendered":"Simple Calculator using Switch Case:"},"content":{"rendered":"\n

<\/h1>\n\n\n\n\n\n

int main() {
char operator;
double num1, num2, result;<\/p>\n\n\n

\n\/\/ Prompt the user for input\nprintf("Enter first number: ");\nscanf("%lf", &num1);\n\nprintf("Enter an operator (+, -, *, \/): ");\nscanf(" %c", &operator);  \/\/ Notice the space before %c to consume any newline character\n\nprintf("Enter second number: ");\nscanf("%lf", &num2);\n\n\/\/ Perform calculation based on operator\nswitch (operator) {\n    case '+':\n        result = num1 + num2;\n        printf("%.2lf + %.2lf = %.2lf\\n", num1, num2, result);\n        break;\n    case '-':\n        result = num1 - num2;\n        printf("%.2lf - %.2lf = %.2lf\\n", num1, num2, result);\n        break;\n    case '*':\n        result = num1 * num2;\n        printf("%.2lf * %.2lf = %.2lf\\n", num1, num2, result);\n        break;\n    case '\/':\n        \/\/ Check for division by zero\n        if (num2 != 0) {\n            result = num1 \/ num2;\n            printf("%.2lf \/ %.2lf = %.2lf\\n", num1, num2, result);\n        } else {\n            printf("Error: Division by zero is not allowed.\\n");\n        }\n        break;\n    default:\n        printf("Error: Invalid operator.\\n");\n        break;\n}\n\nreturn 0;\n<\/pre><\/div>\n\n\n
}<\/p>\n\n\n\n
Explanation:-<\/p>\n\n\n\n
Headers and Main Function<\/strong>: The code begins by including the standard input-output library (<stdio.h><\/code>) and defining the main<\/code> function.<\/p>\n\n\n\n
Variables Declaration<\/strong>: Four variables are declared:<\/p>\n\n\n\n
    \n
  • operator<\/code>: to store the arithmetic operator entered by the user.<\/li>\n\n\n\n
  • num1<\/code> and num2<\/code>: to store the two numbers on which the operation will be performed.<\/li>\n\n\n\n
  • result<\/code>: to store the result of the operation.<\/li>\n<\/ul>\n\n\n\n
    User Input<\/strong>:<\/p>\n\n\n\n
      \n
    • The program prompts the user to enter the first number, the operator, and the second number. The scanf<\/code> function is used to read these inputs.<\/li>\n<\/ul>\n\n\n\n
      Switch Case Statement<\/strong>: This statement evaluates the operator<\/code> variable:<\/p>\n\n\n\n
        \n
      • For each case (+<\/code>, -<\/code>, *<\/code>, \/<\/code>), it performs the corresponding arithmetic operation and prints the result.<\/li>\n\n\n\n
      • If the operator is \/<\/code>, it checks if the second number is zero to prevent division by zero. If it is zero, an error message is displayed.<\/li>\n<\/ul>\n\n\n\n
        Default Case<\/strong>: If the user enters an invalid operator, the program outputs an error message.<\/p>\n\n\n\n
        Example:<\/p>\n\n\n\n
        Suppose a user runs the program and enters the following:<\/p>\n\n\n\n
        Enter first number: 10
        Enter an operator (+, -, *, \/): +
        Enter second number: 5<\/p>\n\n\n\n
        10.00 + 5.00 = 15.00<\/p>\n